Difference between revisions of "2000 AMC 8 Problems/Problem 9"
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The only <math>3</math>-digit power of <math>2</math> beginning with <math>2</math> is <math>256</math>, so the outlined block is filled with | The only <math>3</math>-digit power of <math>2</math> beginning with <math>2</math> is <math>256</math>, so the outlined block is filled with | ||
a <math>\boxed{\text{(D) 6}}</math>. | a <math>\boxed{\text{(D) 6}}</math>. | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/QAeRqTq3a7Y Soo, DRMS, NM | ||
== See Also == | == See Also == | ||
{{AMC8 box|year=2000|num-b=8|num-a=10}} | {{AMC8 box|year=2000|num-b=8|num-a=10}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 22:32, 22 March 2022
Contents
Problem
Three-digit powers of and are used in this cross-number puzzle. What is the only possible digit for the outlined square?
Solution
The -digit powers of are and , so space is filled with a . The only -digit power of beginning with is , so the outlined block is filled with a .
Video Solution
https://youtu.be/QAeRqTq3a7Y Soo, DRMS, NM
See Also
2000 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.