Difference between revisions of "User:CreativeHedgehog/Templates/2 var linear equation"
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− | {{User:CreativeHedgehog/Templates/2 var linear equation|c= | + | {{User:CreativeHedgehog/Templates/2 var linear equation|c=2|b=2|a=4|d=4|e=1|f=0}} |
Note: Do not use this for Alcumus. Also, I am going to build a 3 var'ed one very soon. [https://artofproblemsolving.com/wiki/index.php/User:CreativeHedgehog CreativeHedgehog] 14:42, 7 August 2020 (EDT) | Note: Do not use this for Alcumus. Also, I am going to build a 3 var'ed one very soon. [https://artofproblemsolving.com/wiki/index.php/User:CreativeHedgehog CreativeHedgehog] 14:42, 7 August 2020 (EDT) | ||
+ | |||
+ | It is not fully correct, and I am fixing its bugs. [https://artofproblemsolving.com/wiki/index.php/User:CreativeHedgehog CreativeHedgehog] 15:59, 8 August 2020 (EDT) | ||
</noinclude> | </noinclude> |
Latest revision as of 14:59, 8 August 2020
given a, b, c, d, e, and f, find x and y in the 2 equations below:
{{{a}}}x+{{{b}}}y={{{e}}}
{{{c}}}x+{{{d}}}y={{{f}}}
x=({{{e}}}*{{{d}}}-{{{b}}}*{{{f}}})/({{{a}}}*{{{d}}}-{{{b}}}*{{{c}}})
y=({{{a}}}*{{{f}}}-{{{e}}}*{{{c}}})/({{{a}}}*{{{d}}}-{{{b}}}*{{{c}}})
given a, b, c, d, e, and f, find x and y in the 2 equations below:
4x+2y=1
2x+4y=0
x=(1*4-2*0)/(4*4-2*2)
y=(4*0-1*2)/(4*4-2*2)
Note: Do not use this for Alcumus. Also, I am going to build a 3 var'ed one very soon. CreativeHedgehog 14:42, 7 August 2020 (EDT)
It is not fully correct, and I am fixing its bugs. CreativeHedgehog 15:59, 8 August 2020 (EDT)