Difference between revisions of "2020 AMC 10B Problems/Problem 1"

Revision as of 12:58, 27 March 2020

What is the value of $1-(-2)-3-(-4)-5-(-6)?$

$\textbf{(A)}\ -20 \qquad\textbf{(B)}\ -3 \qquad\textbf{(C)}\ 3 \qquad\textbf{(D)}\ 5 \qquad\textbf{(E)}\ 21$

We know that when we subtract negative numbers, $a-(-b)=a+b$ .

The equation becomes $1+2-3+4-5+6 = \boxed{\textbf{(D)}\ 5}$ ~quacker88

~IceMatrix

2020 AMC 10B (Problems • Answer Key • Resources)
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All AMC 10 Problems and Solutions

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 We know that when we subtract negative numbers, <math>a-(-b)=a+b</math>.
-The equation becomes <math>1+2-3+4-5+6 = \boxed{\textbf{(D)}\ 5}</math> after deleting parentheses. ~quacker88
+The equation becomes <math>1+2-3+4-5+6 = \boxed{\textbf{(D)}\ 5}</math> ~quacker88
 ==Video Solution==