Difference between revisions of "2020 AMC 10B Problems/Problem 2"

Revision as of 15:33, 7 February 2020

What is the value of $1-(-2)-3-(-4)-5-(-6)?$

$\textbf{(A)}\ -20 \qquad\textbf{(B)}\ -3 \qquad\textbf{(C)}\ 3 \qquad\textbf{(D)}\ 5 \qquad\textbf{(E)}\ 21$

A cube with side length $1$ has volume $1^3=1$ , so $5$ of these will have a total volume of $5\cdot1=5$ .

A cube with side length $2$ has volume $2^3=8$ , so $5$ of these will have a total volume of $5\cdot8=40$ .

$5+40=\boxed{\textbf{(E) }21}$ ~quacker88

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 ==Solution==
-A cube with side length <math>1</math> has volume <math>1^3=1</math>. <math>5</math> of these will have a total volume of <math>5\cdot1=5</math>.
+A cube with side length <math>1</math> has volume <math>1^3=1</math>, so <math>5</math> of these will have a total volume of <math>5\cdot1=5</math>.
-A cube with side length <math>2</math> has volume <math>2^3=8</math>. <math>5</math> of these will have a total volume of <math>5\cdot8=40</math>.
+A cube with side length <math>2</math> has volume <math>2^3=8</math>, so <math>5</math> of these will have a total volume of <math>5\cdot8=40</math>.
 <math>5+40=\boxed{\textbf{(E) }21}</math> ~quacker88