Difference between revisions of "2019 AMC 8 Problems/Problem 13"
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==Solution 1== | ==Solution 1== | ||
| − | All the two digit palindromes are multiples of 11. The least 3 digit integer that is the sum of 2 two digit integers is a multiple of 11! The least 3 digit multiple of 11 is 110 | + | All the two digit palindromes are multiples of 11. The least 3 digit integer that is the sum of 2 two digit integers is a multiple of 11! The least 3 digit multiple of 11 is 110! The sum of the digits of 110 is 1+1+0=[A] 2 |
==See Also== | ==See Also== | ||
Revision as of 11:39, 20 November 2019
Problem 13
A 
is a number that has the same value when read from left to right or from right to left. (For example 12321 is a palindrome.) Let 
be the least three-digit integer which is not a palindrome but which is the sum of three distinct two-digit palindromes. What is the sum of the digits of ?
Solution 1
All the two digit palindromes are multiples of 11. The least 3 digit integer that is the sum of 2 two digit integers is a multiple of 11! The least 3 digit multiple of 11 is 110! The sum of the digits of 110 is 1+1+0=[A] 2
See Also
| 2019 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 12 |
Followed by Problem 14 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
