Difference between revisions of "Fundamental Theorem of Sato"
m (Your spelling error is fixed :D) |
(Method 4.) |
||
| Line 18: | Line 18: | ||
There is only one Sato. By Pigeonhole, either Sato is amazing or he isn't (in this case, Sato goes in the unamazing pigeonhole). Fortunately, Sato cannot fit in a pigeonhole; hence, Sato is amazing. (Proved) | There is only one Sato. By Pigeonhole, either Sato is amazing or he isn't (in this case, Sato goes in the unamazing pigeonhole). Fortunately, Sato cannot fit in a pigeonhole; hence, Sato is amazing. (Proved) | ||
| + | |||
| + | Method 4: Proof by Gmass | ||
| + | |||
| + | Gmass is Ssto in cat form. Since Gmass is amazing, and since if <math>a=b</math> and <math>b=c</math>, <math>a=c</math>, Sato is amazing. | ||
Revision as of 21:52, 20 August 2019
The Fundamental Theorem of Sato states the following:
Sato is amazing.
Proof:
Method 1: Proof by Contradiction
Assume, for contradiction, that Sato is not amazing.
This is absurd. Therefore, Sato is amazing. (Proved)
Method 2: Proof by Authority
Whatever AoPS says is correct, and AoPS says that Mr. Sato is amazing. Thus, Mr. Sato is amazing. (Proved)
Method 3: Proof by Pigeonhole
There is only one Sato. By Pigeonhole, either Sato is amazing or he isn't (in this case, Sato goes in the unamazing pigeonhole). Fortunately, Sato cannot fit in a pigeonhole; hence, Sato is amazing. (Proved)
Method 4: Proof by Gmass
Gmass is Ssto in cat form. Since Gmass is amazing, and since if 
and 
, 
, Sato is amazing.
