Difference between revisions of "1957 AHSME Problems/Problem 6"
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+ | ==Problem== | ||
+ | An open box is constructed by starting with a rectangular sheet of metal <math>10</math> in. by <math>14</math> in. and cutting a square of side <math>x</math> inches from each corner. The resulting projections are folded up and the seams welded. The volume of the resulting box is: | ||
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+ | <math>\textbf{(A)}\ 140x - 48x^2 + 4x^3 \qquad \textbf{(B)}\ 140x + 48x^2 + 4x^3\qquad \\ \textbf{(C)}\ 140x+24x^2+x^3\qquad \textbf{(D)}\ 140x-24x^2+x^3\qquad \textbf{(E)}\ \text{none of these}</math> | ||
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+ | ==Solution== | ||
+ | |||
The resulting metal piece looks something like this where the white parts are squares of length <math>x</math>: | The resulting metal piece looks something like this where the white parts are squares of length <math>x</math>: | ||
Revision as of 00:55, 19 June 2019
Problem
An open box is constructed by starting with a rectangular sheet of metal in. by in. and cutting a square of side inches from each corner. The resulting projections are folded up and the seams welded. The volume of the resulting box is:
Solution
The resulting metal piece looks something like this where the white parts are squares of length :
From here, try to visualize the rectangular prism coming together and realize the height is , the length is , and the width is . Therefore, the volume is .
1957 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
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All AHSME Problems and Solutions |
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