Difference between revisions of "1959 AHSME Problems/Problem 38"

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If <math>4x+\sqrt{2x}=1</math>, then <math>x</math>
+
Subtract 4x from both sides so you get:
 +
<math>\sqrt{2x}=1-4x</math>
  
 +
Then just square and simplify to get:
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<math>x=\frac{1}{8}</math>
  
(A) is an integer
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This is answer choice B.
 
 
(B) is fractional
 
 
 
(C) is irrational
 
 
 
(D) is imaginary
 
 
 
(E) may have two different values
 

Revision as of 15:22, 3 March 2019

Subtract 4x from both sides so you get: $\sqrt{2x}=1-4x$

Then just square and simplify to get: $x=\frac{1}{8}$

This is answer choice B.