Difference between revisions of "1958 AHSME Problems/Problem 25"

Latest revision as of 15:16, 19 May 2024

If $\log_{k}{x}\cdot \log_{5}{k} = 3$ , then $x$ equals:

$\textbf{(A)}\ k^6\qquad \textbf{(B)}\ 5k^3\qquad \textbf{(C)}\ k^3\qquad \textbf{(D)}\ 243\qquad \textbf{(E)}\ 125$

125. Rearrange the equation into $\log_{5}{k}\cdot\log_{k}{x} = 3$ which is just $\log_{5}{x} = 3$ and x is 125.

1958 AHSC (Problems • Answer Key • Resources)
Preceded by Problem 24	Followed by Problem 26
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50
All AHSME Problems and Solutions

@@ Line 10: / Line 10: @@
 == Solution ==
-<math>\fbox{}</math>
+. Rearrange the equation into <cmath> \log_{5}{k}\cdot\log_{k}{x} = 3</cmath> which is just <cmath> \log_{5}{x} = 3</cmath> and x is 125.
 == See Also ==