Difference between revisions of "1973 AHSME Problems/Problem 13"
Rockmanex3 (talk | contribs) (Solution to Problem 13 (credit to gaussintraining)) |
Made in 2016 (talk | contribs) (→See Also) |
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Squaring the expression and taking the positive square root (since numerator and denominator are positive) of the result yields | Squaring the expression and taking the positive square root (since numerator and denominator are positive) of the result yields | ||
− | <cmath>\sqrt{(\frac{2(\sqrt2+\sqrt6)}{3\sqrt{2+\sqrt3}})^2}</cmath> | + | <cmath>\sqrt{\left(\frac{2(\sqrt2+\sqrt6)}{3\sqrt{2+\sqrt3}}\right)^2}</cmath> |
− | <cmath>\sqrt{\frac{4(2+4\sqrt{3}+6)}{9(2+\sqrt{3}}}</cmath> | + | <cmath>\sqrt{\frac{4(2+4\sqrt{3}+6)}{9(2+\sqrt{3})}}</cmath> |
− | <cmath>\sqrt{\frac{4(8+4\sqrt{3})}{9(2+\sqrt{3}}}</cmath> | + | <cmath>\sqrt{\frac{4(8+4\sqrt{3})}{9(2+\sqrt{3})}}</cmath> |
<cmath>\sqrt{\frac{16}{9}}</cmath> | <cmath>\sqrt{\frac{16}{9}}</cmath> | ||
<cmath>\frac43</cmath> | <cmath>\frac43</cmath> | ||
Line 21: | Line 21: | ||
==See Also== | ==See Also== | ||
− | {{AHSME | + | {{AHSME 30p box|year=1973|num-b=12|num-a=14}} |
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] |
Latest revision as of 12:59, 20 February 2020
Problem
The fraction is equal to
Solution
Squaring the expression and taking the positive square root (since numerator and denominator are positive) of the result yields
The answer is .
See Also
1973 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 12 |
Followed by Problem 14 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 | ||
All AHSME Problems and Solutions |