Difference between revisions of "2010 AMC 8 Problems/Problem 6"

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Therefore, the answer is <math>\boxed{ \textbf{(E)}\ \text{square} }</math>.
 
Therefore, the answer is <math>\boxed{ \textbf{(E)}\ \text{square} }</math>.
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==Video Solution by @MathTalks==
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https://youtu.be/RhyRqHMXvq0?si=m1R2q8UnLRD-KksT
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==Video Solution by WhyMath==
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https://youtu.be/hoZO5M0raTI
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2010|num-b=5|num-a=7}}
 
{{AMC8 box|year=2010|num-b=5|num-a=7}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 10:25, 18 November 2024

Problem

Which of the following figures has the greatest number of lines of symmetry?

$\textbf{(A)}\ \text{equilateral triangle}$

$\textbf{(B)}\ \text{non-square rhombus}$

$\textbf{(C)}\ \text{non-square rectangle}$

$\textbf{(D)}\ \text{isosceles trapezoid}$

$\textbf{(E)}\ \text{square}$

Solution

An equilateral triangle has $3$ lines of symmetry. A non-square rhombus has $2$ lines of symmetry. A non-square rectangle has $2$ lines of symmetry. An isosceles trapezoid has $1$ line of symmetry. A square has $4$ lines of symmetry.


Therefore, the answer is $\boxed{ \textbf{(E)}\ \text{square} }$.


Video Solution by @MathTalks

https://youtu.be/RhyRqHMXvq0?si=m1R2q8UnLRD-KksT

Video Solution by WhyMath

https://youtu.be/hoZO5M0raTI

See Also

2010 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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