Difference between revisions of "1968 AHSME Problems/Problem 7"

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== Solution ==
 
== Solution ==
<math>\fbox{E}</math>
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The fact that <math>OQ=3</math> only tells us that <math>CQ=9</math>. There are infinitely many triangles with a median which has length 9, so we can make no statement about the length of the median <math>\overline{AP}</math> or the segment <math>\overline{OP}</math>. Thus, <math>OP</math> is <math>\fbox{(E) undetermined}</math>.
  
 
== See also ==
 
== See also ==
{{AHSME box|year=1968|num-b=6|num-a=8}}   
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{{AHSME 35p box|year=1968|num-b=6|num-a=8}}   
  
 
[[Category: Introductory Geometry Problems]]
 
[[Category: Introductory Geometry Problems]]
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 18:13, 17 July 2024

Problem

Let $O$ be the intersection point of medians $AP$ and $CQ$ of triangle $ABC.$ if $OQ$ is 3 inches, then $OP$, in inches, is:

$\text{(A) } 3\quad \text{(B) } \frac{9}{2}\quad \text{(C) } 6\quad \text{(D) } 9\quad \text{(E) } \text{undetermined}$

Solution

The fact that $OQ=3$ only tells us that $CQ=9$. There are infinitely many triangles with a median which has length 9, so we can make no statement about the length of the median $\overline{AP}$ or the segment $\overline{OP}$. Thus, $OP$ is $\fbox{(E) undetermined}$.

See also

1968 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35
All AHSME Problems and Solutions

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