Difference between revisions of "1977 AHSME Problems/Problem 1"
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+ | == Problem 1 == | ||
+ | |||
+ | If <math>y = 2x</math> and <math>z = 2y</math>, then <math>x + y + z</math> equals | ||
+ | |||
+ | <math>\text{(A)}\ x \qquad | ||
+ | \text{(B)}\ 3x \qquad | ||
+ | \text{(C)}\ 5x \qquad | ||
+ | \text{(D)}\ 7x \qquad | ||
+ | \text{(E)}\ 9x</math> | ||
+ | |||
+ | |||
==Solution== | ==Solution== | ||
+ | Solution by e_power_pi_times_i | ||
+ | |||
+ | <math>x+y+z = x+(2x)+(4x) = \boxed{\text{(D)}\ 7x}</math> |
Latest revision as of 11:24, 21 November 2016
Problem 1
If and , then equals
Solution
Solution by e_power_pi_times_i