Difference between revisions of "1953 AHSME Problems/Problem 5"
Katzrockso (talk | contribs) (Created page with "==Problem 5== If <math>\log_6 x=2.5</math>, the value of <math>x</math> is: <math>\textbf{(A)}\ 90 \qquad \textbf{(B)}\ 36 \qquad \textbf{(C)}\ 36\sqrt{6} \qquad \textbf{(D...") |
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\textbf{(E)}\ \text{none of these} </math> | \textbf{(E)}\ \text{none of these} </math> | ||
− | == Solution == | + | == Solution 1 == |
<math>\log_6 x=\frac{5}{2}\implies 2\log_6 x=5\implies \log_6 x^2=5\implies x^2=6^5\implies x=36\sqrt{6}</math>, <math>\fbox{C}</math> | <math>\log_6 x=\frac{5}{2}\implies 2\log_6 x=5\implies \log_6 x^2=5\implies x^2=6^5\implies x=36\sqrt{6}</math>, <math>\fbox{C}</math> | ||
+ | |||
+ | == Solution 2 == | ||
+ | <math>\log_6 x=\frac{5}{2}\implies 6^{\frac{5}{2}}=x \implies \sqrt{6^5}=x \implies 36\sqrt{6} = x</math> | ||
+ | |||
+ | |||
+ | ==See Also== | ||
+ | |||
+ | {{AHSME 50p box|year=1953|num-b=4|num-a=6}} | ||
+ | |||
+ | [[Category:Introductory Algebra Problems]] | ||
+ | {{MAA Notice}} |
Latest revision as of 19:22, 1 April 2017
Contents
Problem 5
If , the value of is:
Solution 1
,
Solution 2
See Also
1953 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 4 |
Followed by Problem 6 | |
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