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Difference between revisions of "2015 AMC 10B Problems/Problem 7"
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==Solution==
 
==Solution==
 
<math>1\diamond2=1-\dfrac{1}{2}=\dfrac{1}{2}</math>, so <math>(1\diamond2)\diamond3=\dfrac{1}{2}\diamond3=\dfrac{1}{2}-\dfrac{1}{3}=\dfrac{1}{6}</math>. Also, <math>2\diamond3=2-\dfrac{1}{3}=\dfrac{5}{3}</math>, so <math>1\diamond(2\diamond3)=1-\dfrac{1}{5/3}=1-\dfrac{3}{5}=\dfrac{2}{5}</math>. Thus, <math>((1\diamond2)\diamond3)-(1\diamond(2\diamond3))=\dfrac{1}{6}-\dfrac{2}{5}=\boxed{\mathbf{(A)}\ -\dfrac{7}{30}}</math>
 
<math>1\diamond2=1-\dfrac{1}{2}=\dfrac{1}{2}</math>, so <math>(1\diamond2)\diamond3=\dfrac{1}{2}\diamond3=\dfrac{1}{2}-\dfrac{1}{3}=\dfrac{1}{6}</math>. Also, <math>2\diamond3=2-\dfrac{1}{3}=\dfrac{5}{3}</math>, so <math>1\diamond(2\diamond3)=1-\dfrac{1}{5/3}=1-\dfrac{3}{5}=\dfrac{2}{5}</math>. Thus, <math>((1\diamond2)\diamond3)-(1\diamond(2\diamond3))=\dfrac{1}{6}-\dfrac{2}{5}=\boxed{\mathbf{(A)}\ -\dfrac{7}{30}}</math>
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==Video Solution 1==
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https://youtu.be/opghB-8aScI
 +
 +
~Education, the Study of Everything
 +
 +
==Video Solution==
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https://youtu.be/SkInNyZkxzA
 +
 +
~savannahsolver
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 +
==See Also==
 +
{{AMC10 box|year=2015|ab=B|num-b=6|num-a=8}}
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{{MAA Notice}}

Latest revision as of 16:11, 2 August 2022

Problem

Consider the operation "minus the reciprocal of," defined by $a\diamond b=a-\frac{1}{b}$. What is $((1\diamond2)\diamond3)-(1\diamond(2\diamond3))$?

$\textbf{(A) } -\dfrac{7}{30} \qquad\textbf{(B) } -\dfrac{1}{6} \qquad\textbf{(C) } 0 \qquad\textbf{(D) } \dfrac{1}{6} \qquad\textbf{(E) } \dfrac{7}{30}$

Solution

$1\diamond2=1-\dfrac{1}{2}=\dfrac{1}{2}$, so $(1\diamond2)\diamond3=\dfrac{1}{2}\diamond3=\dfrac{1}{2}-\dfrac{1}{3}=\dfrac{1}{6}$. Also, $2\diamond3=2-\dfrac{1}{3}=\dfrac{5}{3}$, so $1\diamond(2\diamond3)=1-\dfrac{1}{5/3}=1-\dfrac{3}{5}=\dfrac{2}{5}$. Thus, $((1\diamond2)\diamond3)-(1\diamond(2\diamond3))=\dfrac{1}{6}-\dfrac{2}{5}=\boxed{\mathbf{(A)}\ -\dfrac{7}{30}}$

Video Solution 1

https://youtu.be/opghB-8aScI

~Education, the Study of Everything

Video Solution

https://youtu.be/SkInNyZkxzA

~savannahsolver

See Also

2015 AMC 10B (Problems • Answer Key • Resources)
Preceded by
Problem 6 		Followed by
Problem 8
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 10 Problems and Solutions

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