Difference between revisions of "2014 UNCO Math Contest II Problems/Problem 1"
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== Problem == | == Problem == | ||
+ | |||
+ | The Duchess had a child on May 1st every two years until she had five children. This year the | ||
+ | youngest is <math>1</math> and the ages of the children are <math>1, 3, 5, 7</math>, and <math>9</math>. Alice notices that the sum of the ages | ||
+ | is a perfect square: <math>1 + 3 + 5 + 7 + 9 = 25</math>. How old will the youngest be the next time the sum of | ||
+ | the ages of the five children is a perfect square, and what is that perfect square? | ||
+ | |||
== Solution == | == Solution == | ||
+ | We know that the sum of the ages is 25. To get another perfect square, we need to multiply it by a perfect square, so we get 100 for the next perfect square. We know their ages are (N-4)+(N-2)+(N)+(N+2)+(N+4)=100. Solving for N gives us 20, so the youngest is 20-4=16. | ||
== See also == | == See also == | ||
− | {{ | + | {{UNCO Math Contest box|year=2014|n=II|before=First Question|num-a=2}} |
[[Category:Introductory Number Theory Problems]] | [[Category:Introductory Number Theory Problems]] |
Latest revision as of 15:31, 23 December 2014
Problem
The Duchess had a child on May 1st every two years until she had five children. This year the youngest is and the ages of the children are , and . Alice notices that the sum of the ages is a perfect square: . How old will the youngest be the next time the sum of the ages of the five children is a perfect square, and what is that perfect square?
Solution
We know that the sum of the ages is 25. To get another perfect square, we need to multiply it by a perfect square, so we get 100 for the next perfect square. We know their ages are (N-4)+(N-2)+(N)+(N+2)+(N+4)=100. Solving for N gives us 20, so the youngest is 20-4=16.
See also
2014 UNCO Math Contest II (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
All UNCO Math Contest Problems and Solutions |