Difference between revisions of "1970 AHSME Problems/Problem 1"
(Created page with "== Problem == The fourth power of <math>\sqrt{1+\sqrt{1+\sqrt{1}}}</math> is <math>\text{(A) } \sqrt{2}+\sqrt{3}\quad \text{(B) } \tfrac{1}{2}(7+3\sqrt{5})\quad \text{(C) } 1+2...") |
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== Solution == | == Solution == | ||
| − | <math>\ | + | We can simplify the expression to <math>\sqrt{1+\sqrt{2}}</math> Then we square it so it is now <math>1+\sqrt{2}</math>. We still have to square it one more time, getting <math>\boxed{(E)\ 3+2\sqrt{2}}</math>. |
== See also == | == See also == | ||
| − | {{AHSME box|year=1970|num-b=1|num-a=2}} | + | {{AHSME 35p box|year=1970|num-b=1|num-a=2}} |
[[Category: Introductory Algebra Problems]] | [[Category: Introductory Algebra Problems]] | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 20:45, 16 February 2016
Problem
The fourth power of 
is
Solution
We can simplify the expression to 
Then we square it so it is now 
. We still have to square it one more time, getting 
.
See also
| 1970 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
