Difference between revisions of "1991 AHSME Problems/Problem 15"

m
(Added a solution with explanation)
 
(2 intermediate revisions by one other user not shown)
Line 2: Line 2:
  
 
A circular table has 60 chairs around it. There are <math>N</math> people seated at this table in such a way that the next person seated must sit next to someone. What is the smallest possible value for <math>N</math>?
 
A circular table has 60 chairs around it. There are <math>N</math> people seated at this table in such a way that the next person seated must sit next to someone. What is the smallest possible value for <math>N</math>?
 +
 +
<math>\text{(A) } 15\quad
 +
\text{(B) } 20\quad
 +
\text{(C) } 30\quad
 +
\text{(D) } 40\quad
 +
\text{(E) } 58</math>
 +
 
== Solution ==
 
== Solution ==
<math>\fbox{}</math>
+
<math>\fbox{B}</math> If we fill every third chair with a person, then the condition is satisfied, giving <math>N=20</math>. Decreasing <math>N</math> any further means there is at least one gap of <math>4</math>, so that the person can sit themselves in the middle (seat <math>2</math> of <math>4</math>) and not be next to anyone. Hence the minimum value of <math>N</math> is <math>20</math>.
  
 
== See also ==
 
== See also ==

Latest revision as of 16:38, 23 February 2018

Problem

A circular table has 60 chairs around it. There are $N$ people seated at this table in such a way that the next person seated must sit next to someone. What is the smallest possible value for $N$?

$\text{(A) } 15\quad \text{(B) } 20\quad \text{(C) } 30\quad \text{(D) } 40\quad \text{(E) } 58$

Solution

$\fbox{B}$ If we fill every third chair with a person, then the condition is satisfied, giving $N=20$. Decreasing $N$ any further means there is at least one gap of $4$, so that the person can sit themselves in the middle (seat $2$ of $4$) and not be next to anyone. Hence the minimum value of $N$ is $20$.

See also

1991 AHSME (ProblemsAnswer KeyResources)
Preceded by
Problem 14
Followed by
Problem 16
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
All AHSME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png