Difference between revisions of "1967 AHSME Problems/Problem 6"
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== Solution == | == Solution == | ||
| + | The desired expression is equal to <math>4^{x+1} - 4^{x}</math> | ||
| + | Using the fact that <math>4^{x+1}</math>=<math>4^{x}*4</math>, we see that the answer is | ||
| + | <math>3*4^{x}</math> | ||
<math>\fbox{D}</math> | <math>\fbox{D}</math> | ||
== See also == | == See also == | ||
| − | {{AHSME box|year=1967|num-b=5|num-a=7}} | + | {{AHSME 40p box|year=1967|num-b=5|num-a=7}} |
[[Category:Introductory Algebra Problems]] | [[Category:Introductory Algebra Problems]] | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Latest revision as of 00:35, 16 August 2023
Problem
If 
then 
equals:
Solution
The desired expression is equal to 
Using the fact that 
=
, we see that the answer is
See also
| 1967 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
