Difference between revisions of "1966 AHSME Problems/Problem 15"

Latest revision as of 21:11, 14 January 2018

If $x-y>x$ and $x+y<y$ , then

$\text{(A) } y<x \quad \text{(B) } x<y \quad \text{(C) } x<y<0 \quad \text{(D) } x<0,y<0 \quad \text{(E) } x<0,y>0$

From $x-y>x$ , we get that $-y>0\implies y<0$ . From $x+y<y$ , we get that $x<0$ . So, our final answer is $\fbox{D}$ .

1966 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 14	Followed by Problem 16
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30
All AHSME Problems and Solutions

@@ Line 5: / Line 5: @@
 == Solution ==
-<math>\fbox{D}</math>
+From <math>x-y>x</math>, we get that <math>-y>0\implies y<0</math>.
+From <math>x+y<y</math>, we get that <math>x<0</math>.
+So, our final answer is <math>\fbox{D}</math>.
 == See also ==