Difference between revisions of "2014 AMC 12B Problems/Problem 4"

(Added templates)
m (Solution)
 
(5 intermediate revisions by 4 users not shown)
Line 3: Line 3:
 
Susie pays for <math> 4 </math> muffins and <math> 3 </math> bananas. Calvin spends twice as much paying for <math> 2 </math> muffins and <math> 16 </math> bananas. A muffin is how many times as expensive as a banana?
 
Susie pays for <math> 4 </math> muffins and <math> 3 </math> bananas. Calvin spends twice as much paying for <math> 2 </math> muffins and <math> 16 </math> bananas. A muffin is how many times as expensive as a banana?
  
<math> \textbf{(A)}\ \frac{3}{2}\qquad\textbf{(B)}\ \frac{5}{3}\qquad\textbf{(C)}\ \frac{7}{4}\qquad\textbf{(D)}}\ 2\qquad\textbf{(E)}\ \frac{13}{4} </math>
+
<math> \textbf{(A)}\ \frac{3}{2}\qquad\textbf{(B)}\ \frac{5}{3}\qquad\textbf{(C)}\ \frac{7}{4}\qquad\textbf{(D)}\ 2\qquad\textbf{(E)}\ \frac{13}{4} </math>
  
 
==Solution==
 
==Solution==
  
Let <math>m</math> stand for the cost of a muffin, and let <math>b</math> stand for the value of a banana. We we need to find <math>\frac{m}{b}</math>, the ratio of the price of the muffins to that of the bananas. We have
+
Let <math>m</math> stand for the cost of a muffin, and let <math>b</math> stand for the value of a banana. We need to find <math>\frac{m}{b}</math>, the ratio of the price of the muffins to that of the bananas. We have
 
<cmath>2(4m + 3b) = 2m + 16b </cmath>
 
<cmath>2(4m + 3b) = 2m + 16b </cmath>
 
<cmath>6m = 10b </cmath>
 
<cmath>6m = 10b </cmath>
 
<cmath>\frac{m}{b} = \boxed{\textbf{(B)}\ \frac{5}{3}}</cmath>
 
<cmath>\frac{m}{b} = \boxed{\textbf{(B)}\ \frac{5}{3}}</cmath>
  
 +
==Video Solution 1 (Quick and Easy)==
 +
https://youtu.be/K4HupKj78Yc
 +
 +
~Education, the Study of Everything
 +
 +
== See also ==
 
{{AMC12 box|year=2014|ab=B|num-b=3|num-a=5}}
 
{{AMC12 box|year=2014|ab=B|num-b=3|num-a=5}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 17:30, 17 October 2024

Problem

Susie pays for $4$ muffins and $3$ bananas. Calvin spends twice as much paying for $2$ muffins and $16$ bananas. A muffin is how many times as expensive as a banana?

$\textbf{(A)}\ \frac{3}{2}\qquad\textbf{(B)}\ \frac{5}{3}\qquad\textbf{(C)}\ \frac{7}{4}\qquad\textbf{(D)}\ 2\qquad\textbf{(E)}\ \frac{13}{4}$

Solution

Let $m$ stand for the cost of a muffin, and let $b$ stand for the value of a banana. We need to find $\frac{m}{b}$, the ratio of the price of the muffins to that of the bananas. We have \[2(4m + 3b) = 2m + 16b\] \[6m = 10b\] \[\frac{m}{b} = \boxed{\textbf{(B)}\ \frac{5}{3}}\]

Video Solution 1 (Quick and Easy)

https://youtu.be/K4HupKj78Yc

~Education, the Study of Everything

See also

2014 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png