Difference between revisions of "2014 AMC 10B Problems/Problem 25"

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==Problem==
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#redirect [[2014 AMC 12B Problems/Problem 22]]
In a small pond there are eleven lily pads in a row labeled <math>0</math> through <math>10</math>. A frog is sitting on pad <math>1</math>. When the frog is on pad <math>N</math>, <math>0<N<10</math>, it will jump to pad <math>N-1</math> with probability <math>\frac{N}{10}</math> and to pad <math>N+1</math> with probability <math>1-\frac{N}{10}</math>. Each jump is independent of the previous jumps. If the frog reaches pad <math>0</math> it will be eaten by a patiently waiting snake. If the frog reaches pad <math>10</math> it will exit the pond, never to return. what is the probability that the frog will escape being eaten by the snake?
 
 
 
<math> \textbf {(A) } \frac{32}{79} \qquad \textbf {(B) } \frac{161}{384} \qquad \textbf {(C) } \frac{63}{146} \qquad \textbf {(D) } \frac{7}{16} \qquad \textbf {(E) } \frac{1}{2} </math>
 
 
 
==Solution==
 
No matter how the movement of the frog might be, the probabilities of its being killed and its surviving are the same. Therefore, the chance, in which the frog escape successfully, is <math>\frac{1}{2}boxed{textbf(E)}</math>
 
 
 
==See Also==
 
{{AMC10 box|year=2014|ab=B|num-b=24|after=Last Problem}}
 
{{MAA Notice}}
 

Latest revision as of 13:21, 21 November 2020