Difference between revisions of "2013 AMC 10A Problems/Problem 2"
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==Solution== | ==Solution== | ||
− | To get how many cups we need, we realize that we simply need to divide the number of cups needed by the number of cups collected in her measuring cup each time. Thus, we need to evaluate the fraction <math>\frac{2\frac{1}{2}}{\frac{1}{4}}</math>. Simplifying, this is equal to <math>\frac{5}{2}(4) = | + | To get how many cups we need, we realize that we simply need to divide the number of cups needed by the number of cups collected in her measuring cup each time. Thus, we need to evaluate the fraction <math>\frac{2\frac{1}{2}}{\frac{1}{4}}</math>. Simplifying, this is equal to <math>\frac{5}{2}(4) = \boxed{\textbf{(B) }10}</math> |
+ | |||
+ | ==Video Solution (CREATIVE THINKING)== | ||
+ | https://youtu.be/yjRXkJJ6Vg0 | ||
+ | |||
+ | ~Education, the Study of Everything | ||
+ | |||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/E-9k3t6AQ68 | ||
+ | |||
+ | ~savannahsolver | ||
+ | |||
+ | ==See Also== | ||
+ | |||
+ | {{AMC10 box|year=2013|ab=A|num-b=1|num-a=3}} | ||
+ | {{MAA Notice}} |
Latest revision as of 12:10, 1 July 2023
Problem
Alice is making a batch of cookies and needs cups of sugar. Unfortunately, her measuring cup holds only cup of sugar. How many times must she fill that cup to get the correct amount of sugar?
Solution
To get how many cups we need, we realize that we simply need to divide the number of cups needed by the number of cups collected in her measuring cup each time. Thus, we need to evaluate the fraction . Simplifying, this is equal to
Video Solution (CREATIVE THINKING)
~Education, the Study of Everything
Video Solution
~savannahsolver
See Also
2013 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 1 |
Followed by Problem 3 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.