Difference between revisions of "2007 AMC 8 Problems/Problem 2"

(Solution)
 
(4 intermediate revisions by 4 users not shown)
Line 2: Line 2:
 
<math>650</math> students were surveyed about their pasta preferences. The choices were lasagna, manicotti, ravioli and spaghetti. The results of the survey are displayed in the bar graph. What is the ratio of the number of students who preferred spaghetti to the number of students who preferred manicotti?
 
<math>650</math> students were surveyed about their pasta preferences. The choices were lasagna, manicotti, ravioli and spaghetti. The results of the survey are displayed in the bar graph. What is the ratio of the number of students who preferred spaghetti to the number of students who preferred manicotti?
  
<center>[[Image:AMC8_2007_2.png]]</center>
+
<asy>
 +
size(200);
 +
defaultpen(linewidth(0.7));
 +
defaultpen(fontsize(8));
 +
draw(origin--(0,250));
 +
int i;
 +
for(i=0; i<6; i=i+1) {
 +
draw((0,50*i)--(5,50*i));
 +
}
 +
filldraw((25,0)--(75,0)--(75,150)--(25,150)--cycle, gray, black);
 +
filldraw((75,0)--(125,0)--(125,100)--(75,100)--cycle, gray, black);
 +
filldraw((125,0)--(175,0)--(175,150)--(125,150)--cycle, gray, black);
 +
filldraw((225,0)--(175,0)--(175,250)--(225,250)--cycle, gray, black);
 +
label("$50$", (0,50), W);
 +
label("$100$", (0,100), W);
 +
label("$150$", (0,150), W);
 +
label("$200$", (0,200), W);
 +
label("$250$", (0,250), W);
 +
label(rotate(90)*"Lasagna", (50,0), S);
 +
label(rotate(90)*"Manicotti", (100,0), S);
 +
label(rotate(90)*"Ravioli", (150,0), S);
 +
label(rotate(90)*"Spaghetti", (200,0), S);
 +
label(rotate(90)*"$\mbox{Number of People}$", (-40,140), W);
 +
</asy>
  
 
<math>\mathrm{(A)} \frac{2}{5} \qquad \mathrm{(B)} \frac{1}{2} \qquad \mathrm{(C)} \frac{5}{4} \qquad \mathrm{(D)} \frac{5}{3} \qquad \mathrm{(E)} \frac{5}{2}</math>
 
<math>\mathrm{(A)} \frac{2}{5} \qquad \mathrm{(B)} \frac{1}{2} \qquad \mathrm{(C)} \frac{5}{4} \qquad \mathrm{(D)} \frac{5}{3} \qquad \mathrm{(E)} \frac{5}{2}</math>
Line 8: Line 31:
 
== Solution ==
 
== Solution ==
  
The answer is (number of students who preferred spaghetti)/(number of students who preferred manicotti)
+
The answer is <math>\dfrac{\text{number of students who preferred spaghetti}}{\text{number of students who preferred manicotti}}</math>
  
 
So,
 
So,
Line 19: Line 42:
  
 
The answer is <math> \boxed{\textbf{(E)}\ \dfrac{5}{2}} </math>
 
The answer is <math> \boxed{\textbf{(E)}\ \dfrac{5}{2}} </math>
 +
 +
==Video Solution by SpreadTheMathLove==
 +
https://www.youtube.com/watch?v=omFpSGMWhFc
 +
 +
==Video Solution by WhyMath==
 +
https://youtu.be/rcxZpl44uP0
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2007|num-b=1|num-a=3}}
 
{{AMC8 box|year=2007|num-b=1|num-a=3}}
 +
{{MAA Notice}}

Latest revision as of 16:29, 28 October 2024

Problem

$650$ students were surveyed about their pasta preferences. The choices were lasagna, manicotti, ravioli and spaghetti. The results of the survey are displayed in the bar graph. What is the ratio of the number of students who preferred spaghetti to the number of students who preferred manicotti?

[asy] size(200); defaultpen(linewidth(0.7)); defaultpen(fontsize(8)); draw(origin--(0,250)); int i; for(i=0; i<6; i=i+1) { draw((0,50*i)--(5,50*i)); } filldraw((25,0)--(75,0)--(75,150)--(25,150)--cycle, gray, black); filldraw((75,0)--(125,0)--(125,100)--(75,100)--cycle, gray, black); filldraw((125,0)--(175,0)--(175,150)--(125,150)--cycle, gray, black); filldraw((225,0)--(175,0)--(175,250)--(225,250)--cycle, gray, black); label("$50$", (0,50), W); label("$100$", (0,100), W); label("$150$", (0,150), W); label("$200$", (0,200), W); label("$250$", (0,250), W); label(rotate(90)*"Lasagna", (50,0), S); label(rotate(90)*"Manicotti", (100,0), S); label(rotate(90)*"Ravioli", (150,0), S); label(rotate(90)*"Spaghetti", (200,0), S); label(rotate(90)*"$\mbox{Number of People}$", (-40,140), W); [/asy]

$\mathrm{(A)} \frac{2}{5} \qquad \mathrm{(B)} \frac{1}{2} \qquad \mathrm{(C)} \frac{5}{4} \qquad \mathrm{(D)} \frac{5}{3} \qquad \mathrm{(E)} \frac{5}{2}$

Solution

The answer is $\dfrac{\text{number of students who preferred spaghetti}}{\text{number of students who preferred manicotti}}$

So,

$\frac{250}{100}$

Simplify,

$\frac{5}{2}$

The answer is $\boxed{\textbf{(E)}\ \dfrac{5}{2}}$

Video Solution by SpreadTheMathLove

https://www.youtube.com/watch?v=omFpSGMWhFc

Video Solution by WhyMath

https://youtu.be/rcxZpl44uP0

See Also

2007 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png