Difference between revisions of "2011 AMC 8 Problems/Problem 2"
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The area of a rectangle is given by the formula length times width. Karl's garden is <math>20 \times 45 = 900</math> square feet and Makenna's garden is <math>25 \times 40 = 1000</math> square feet. Since <math>1000 > 900,</math> Makenna's garden is larger by <math>1000-900=100</math> square feet. <math>\Rightarrow \boxed{ \textbf{(E)}\ \text{Makenna's garden is larger by 100 square feet.} }</math> | The area of a rectangle is given by the formula length times width. Karl's garden is <math>20 \times 45 = 900</math> square feet and Makenna's garden is <math>25 \times 40 = 1000</math> square feet. Since <math>1000 > 900,</math> Makenna's garden is larger by <math>1000-900=100</math> square feet. <math>\Rightarrow \boxed{ \textbf{(E)}\ \text{Makenna's garden is larger by 100 square feet.} }</math> | ||
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| + | ==Video Solution by WhyMath== | ||
| + | https://youtu.be/CzAPGrFs0xs | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2011|num-b=1|num-a=3}} | {{AMC8 box|year=2011|num-b=1|num-a=3}} | ||
| + | {{MAA Notice}} | ||
Latest revision as of 10:01, 18 November 2024
Problem
Karl's rectangular vegetable garden is 
feet by 
feet, and Makenna's is 
feet by 
feet. Whose garden is larger in area?
Solution
The area of a rectangle is given by the formula length times width. Karl's garden is 
square feet and Makenna's garden is 
square feet. Since 
Makenna's garden is larger by 
square feet. 
Video Solution by WhyMath
See Also
| 2011 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
