Difference between revisions of "2011 IMO Problems"
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== Day 1 == | == Day 1 == | ||
− | === Problem 1 | + | === Problem 1 === |
− | Given any set <math>A = \{a_1, a_2, a_3, a_4\}</math> of four distinct positive integers, | + | Given any set <math>A = \{a_1, a_2, a_3, a_4\}</math> of four distinct positive integers, let <math>s(A)=a_1+a_2+a_3+a_4</math> be the sum of the positive integers in <math>A</math>. Let <math>n(A)</math> denote the number of pairs <math>(i,j)</math> with <math>1 \le i < j \le 4</math> for which <math>a_i+a_j</math> divides <math>s(A)</math>. Find all sets <math>A</math> of four distinct positive integers which achieve the largest possible value of <math>n(A)</math>. |
− | '' | + | ''Author: Fernando Campos, Mexico'' |
[[2011 IMO Problems/Problem 1 | Solution]] | [[2011 IMO Problems/Problem 1 | Solution]] | ||
− | === Problem 2 | + | === Problem 2 === |
Let <math>S</math> be a finite set of at least two points in the plane. Assume that no three points of <math>S</math> are collinear. A windmill is a process that starts with a line <math>l</math> going through a single point <math>P \in S</math>. The line rotates clockwise about the pivot <math>P</math> until the first time that the line meets some other point belonging to <math>S</math>. This point, <math>Q</math>, takes over as the new pivot, and the line now rotates clockwise about <math>Q</math>, until it next meets a point of <math>S</math>. This process continues indefinitely. | Let <math>S</math> be a finite set of at least two points in the plane. Assume that no three points of <math>S</math> are collinear. A windmill is a process that starts with a line <math>l</math> going through a single point <math>P \in S</math>. The line rotates clockwise about the pivot <math>P</math> until the first time that the line meets some other point belonging to <math>S</math>. This point, <math>Q</math>, takes over as the new pivot, and the line now rotates clockwise about <math>Q</math>, until it next meets a point of <math>S</math>. This process continues indefinitely. | ||
Show that we can choose a point <math>P</math> in <math>S</math> and a line <math>l</math> going through <math>P</math> such that the resulting windmill uses each point of <math>S</math> as a pivot infinitely many times. | Show that we can choose a point <math>P</math> in <math>S</math> and a line <math>l</math> going through <math>P</math> such that the resulting windmill uses each point of <math>S</math> as a pivot infinitely many times. | ||
+ | |||
+ | ''Author: Geoffrey Smith, United Kingdom'' | ||
[[2011 IMO Problems/Problem 2 | Solution]] | [[2011 IMO Problems/Problem 2 | Solution]] | ||
− | === Problem 3 | + | === Problem 3 === |
− | Let <math>f : R \rightarrow R</math> be a real-valued function defined on the set of real numbers that satisfies | + | Let <math>f : \mathbb{R} \rightarrow \mathbb{R}</math> be a real-valued function defined on the set of real numbers that satisfies |
<math>f(x + y) \le yf(x) + f(f(x))</math> for all real numbers <math>x</math> and <math>y</math>. Prove that <math>f(x)=0</math> for all <math>x \le 0</math>. | <math>f(x + y) \le yf(x) + f(f(x))</math> for all real numbers <math>x</math> and <math>y</math>. Prove that <math>f(x)=0</math> for all <math>x \le 0</math>. | ||
+ | |||
+ | ''Author: Igor Voronovich, Belarus'' | ||
[[2011 IMO Problems/Problem 3 | Solution]] | [[2011 IMO Problems/Problem 3 | Solution]] | ||
− | |||
== Day 2 == | == Day 2 == | ||
Line 26: | Line 29: | ||
Let <math>n > 0</math> be an integer. We are given a balance and <math>n</math> weights of weight <math>2^0, 2^1,\ldots, 2^{n-1}</math> . We are to place each of the <math>n</math> weights on the balance, one after another, in such a way that the right pan is never heavier than the left pan. At each step we choose one of the weights that has not yet been placed on the balance, and place it on either the left pan or the right pan, until all of the weights have been placed. | Let <math>n > 0</math> be an integer. We are given a balance and <math>n</math> weights of weight <math>2^0, 2^1,\ldots, 2^{n-1}</math> . We are to place each of the <math>n</math> weights on the balance, one after another, in such a way that the right pan is never heavier than the left pan. At each step we choose one of the weights that has not yet been placed on the balance, and place it on either the left pan or the right pan, until all of the weights have been placed. | ||
Determine the number of ways in which this can be done. | Determine the number of ways in which this can be done. | ||
+ | |||
+ | ''Author: Morteza Saghafian, Iran'' | ||
[[2011 IMO Problems/Problem 4 | Solution]] | [[2011 IMO Problems/Problem 4 | Solution]] | ||
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=== Problem 5. === | === Problem 5. === | ||
Let <math>f</math> be a function from the set of integers to the set of positive integers. Suppose that, for any two integers <math>m</math> and <math>n</math>, the difference <math>f(m) - f(n)</math> is divisible by <math>f(m - n)</math>. Prove that, for all integers <math>m</math> and <math>n</math> with <math>f(m) \le f(n)</math>, the number <math>f(n)</math> is divisible by <math>f(m)</math>. | Let <math>f</math> be a function from the set of integers to the set of positive integers. Suppose that, for any two integers <math>m</math> and <math>n</math>, the difference <math>f(m) - f(n)</math> is divisible by <math>f(m - n)</math>. Prove that, for all integers <math>m</math> and <math>n</math> with <math>f(m) \le f(n)</math>, the number <math>f(n)</math> is divisible by <math>f(m)</math>. | ||
+ | |||
+ | ''Author: Mahyar Sefidgaran, Iran'' | ||
[[2011 IMO Problems/Problem 5 | Solution]] | [[2011 IMO Problems/Problem 5 | Solution]] | ||
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=== Problem 6. === | === Problem 6. === | ||
Let <math>ABC</math> be an acute triangle with circumcircle <math>\Gamma</math>. Let <math>l</math> be a tangent line to <math>\Gamma</math>, and let <math>l_a</math>, <math>l_b</math> and <math>l_c</math> be the lines obtained by reflecting <math>l</math> in the lines <math>BC</math>, <math>CA</math> and <math>AB</math>, respectively. Show that the circumcircle of the triangle determined by the lines <math>l_a</math>, <math>l_b</math> and <math>l_c</math> is tangent to the circle <math>\Gamma</math>. | Let <math>ABC</math> be an acute triangle with circumcircle <math>\Gamma</math>. Let <math>l</math> be a tangent line to <math>\Gamma</math>, and let <math>l_a</math>, <math>l_b</math> and <math>l_c</math> be the lines obtained by reflecting <math>l</math> in the lines <math>BC</math>, <math>CA</math> and <math>AB</math>, respectively. Show that the circumcircle of the triangle determined by the lines <math>l_a</math>, <math>l_b</math> and <math>l_c</math> is tangent to the circle <math>\Gamma</math>. | ||
+ | |||
+ | ''Author: Japan'' | ||
[[2011 IMO Problems/Problem 6 | Solution]] | [[2011 IMO Problems/Problem 6 | Solution]] | ||
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* [[2011 IMO]] | * [[2011 IMO]] | ||
* [http://www.artofproblemsolving.com/Forum/resources.php?c=1&cid=16&year=2011&sid=8fa5e6d20f9aad1a4dd4efa73519b417 2011 IMO Problems on the Resources page] | * [http://www.artofproblemsolving.com/Forum/resources.php?c=1&cid=16&year=2011&sid=8fa5e6d20f9aad1a4dd4efa73519b417 2011 IMO Problems on the Resources page] | ||
+ | |||
+ | {{IMO box|year=2011|before=[[2010 IMO Problems]]|after=[[2012 IMO Problems]]}} |
Latest revision as of 23:12, 17 February 2021
Problems of the 52st IMO 2011 in Amsterdam, Netherlands.
Contents
Day 1
Problem 1
Given any set of four distinct positive integers, let be the sum of the positive integers in . Let denote the number of pairs with for which divides . Find all sets of four distinct positive integers which achieve the largest possible value of .
Author: Fernando Campos, Mexico
Problem 2
Let be a finite set of at least two points in the plane. Assume that no three points of are collinear. A windmill is a process that starts with a line going through a single point . The line rotates clockwise about the pivot until the first time that the line meets some other point belonging to . This point, , takes over as the new pivot, and the line now rotates clockwise about , until it next meets a point of . This process continues indefinitely. Show that we can choose a point in and a line going through such that the resulting windmill uses each point of as a pivot infinitely many times.
Author: Geoffrey Smith, United Kingdom
Problem 3
Let be a real-valued function defined on the set of real numbers that satisfies for all real numbers and . Prove that for all .
Author: Igor Voronovich, Belarus
Day 2
Problem 4.
Let be an integer. We are given a balance and weights of weight . We are to place each of the weights on the balance, one after another, in such a way that the right pan is never heavier than the left pan. At each step we choose one of the weights that has not yet been placed on the balance, and place it on either the left pan or the right pan, until all of the weights have been placed. Determine the number of ways in which this can be done.
Author: Morteza Saghafian, Iran
Problem 5.
Let be a function from the set of integers to the set of positive integers. Suppose that, for any two integers and , the difference is divisible by . Prove that, for all integers and with , the number is divisible by .
Author: Mahyar Sefidgaran, Iran
Problem 6.
Let be an acute triangle with circumcircle . Let be a tangent line to , and let , and be the lines obtained by reflecting in the lines , and , respectively. Show that the circumcircle of the triangle determined by the lines , and is tangent to the circle .
Author: Japan
Resources
2011 IMO (Problems) • Resources | ||
Preceded by 2010 IMO Problems |
1 • 2 • 3 • 4 • 5 • 6 | Followed by 2012 IMO Problems |
All IMO Problems and Solutions |