Difference between revisions of "1974 AHSME Problems/Problem 1"
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==See Also== | ==See Also== | ||
{{AHSME box|year=1974|before=First Problem|num-a=2}} | {{AHSME box|year=1974|before=First Problem|num-a=2}} | ||
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| + | [[Category:Introductory Algebra Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 11:42, 5 July 2013
Problem
If 
or 
and 
or 
, then 
is equivalent to
Solution
To clear out the fractions, we multiply both sides of the equation by 
to get 
, or 
. From this, we have 
. We can factor an 
out of the RHS, and so 
.
See Also
| 1974 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by First Problem |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
