Difference between revisions of "1951 AHSME Problems/Problem 12"
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== Solution == | == Solution == | ||
| − | {{ | + | Using the formula <math>\frac{|60h-11m|}{2}</math>, where <math>h</math> is the hour time and <math>m</math> is the minute time, we get that the angle is <math>\frac{|60(2)-11(15)|}{2}=\frac{|120-165|}{2}=\frac{45}{2}=\boxed{\textbf{(C)}\ 22\frac {1}{2}^{\circ} }</math> |
== See Also == | == See Also == | ||
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[[Category:Introductory Geometry Problems]] | [[Category:Introductory Geometry Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 11:20, 5 July 2013
Problem
At 
o'clock, the hour and minute hands of a clock form an angle of:
Solution
Using the formula 
, where 
is the hour time and 
is the minute time, we get that the angle is 
See Also
| 1951 AHSC (Problems • Answer Key • Resources) | ||
| Preceded by Problem 11 |
Followed by Problem 13 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 • 31 • 32 • 33 • 34 • 35 • 36 • 37 • 38 • 39 • 40 • 41 • 42 • 43 • 44 • 45 • 46 • 47 • 48 • 49 • 50 | ||
| All AHSME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
