Difference between revisions of "1950 AHSME Problems/Problem 8"

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==See Also==
 
==See Also==
  
{{AHSME box|year=1950|num-b=7|num-a=9}}
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{{AHSME 50p box|year=1950|num-b=7|num-a=9}}
  
 
[[Category:Introductory Algebra Problems]]
 
[[Category:Introductory Algebra Problems]]
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{{MAA Notice}}

Latest revision as of 10:58, 5 July 2013

Problem

If the radius of a circle is increased $100\%$, the area is increased:

$\textbf{(A)}\ 100\%\qquad\textbf{(B)}\ 200\%\qquad\textbf{(C)}\ 300\%\qquad\textbf{(D)}\ 400\%\qquad\textbf{(E)}\ \text{By none of these}$

Solution

Increasing by $100\%$ is the same as doubling the radius. If we let $r$ be the radius of the old circle, then the radius of the new circle is $2r.$

Since the area of the circle is given by the formula $\pi r^2,$ the area of the new circle is $\pi (2r)^2 = 4\pi r^2.$ The area is quadrupled, or increased by $\boxed{\mathrm{(C) }300\%.}$

See Also

1950 AHSC (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 9
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All AHSME Problems and Solutions

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