Difference between revisions of "1994 AJHSME Problems/Problem 5"
(Created page with "==Problem== Given that <math>\text{1 mile} = \text{8 furlongs}</math> and <math>\text{1 furlong} = \text{40 rods}</math>, the number of rods in one mile is <math>\text{(A)}\ 5 ...") |
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<math>\text{(A)}\ 5 \qquad \text{(B)}\ 320 \qquad \text{(C)}\ 660 \qquad \text{(D)}\ 1760 \qquad \text{(E)}\ 5280</math> | <math>\text{(A)}\ 5 \qquad \text{(B)}\ 320 \qquad \text{(C)}\ 660 \qquad \text{(D)}\ 1760 \qquad \text{(E)}\ 5280</math> | ||
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| + | ==Solution== | ||
| + | <cmath>(1\ \text{mile}) \left( \frac{8\ \text{furlongs}}{1\ \text{mile}} \right) \left( \frac{40\ \text{rods}}{1\ \text{furlong}} \right) = \boxed{\text{(B)}\ 320}</cmath> | ||
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| + | ==See Also== | ||
| + | {{AJHSME box|year=1994|num-b=4|num-a=6}} | ||
| + | {{MAA Notice}} | ||
Latest revision as of 23:13, 4 July 2013
Problem
Given that 
and 
, the number of rods in one mile is
Solution
![\[(1\ \text{mile}) \left( \frac{8\ \text{furlongs}}{1\ \text{mile}} \right) \left( \frac{40\ \text{rods}}{1\ \text{furlong}} \right) = \boxed{\text{(B)}\ 320}\]](http://latex.artofproblemsolving.com/e/a/0/ea00765750fa695fb2636a3a5d8164c34ae313c0.png)
See Also
| 1994 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
