Difference between revisions of "1997 AJHSME Problems/Problem 4"
Bluecarneal (talk | contribs) (Created page with "We need number of words between <math>30\times150=4500</math> and <math>45\times150=6750</math>. The only such choice is <math>\boxed{\textbf{(E)}}</math>.") |
|||
| (2 intermediate revisions by 2 users not shown) | |||
| Line 1: | Line 1: | ||
| − | + | ==Problem== | |
| + | |||
| + | Julie is preparing a speech for her class. Her speech must last between one-half hour and three-quarters of an hour. The ideal rate of speech is 150 words per minute. If Julie speaks at the ideal rate, which of the following number of words would be an appropriate length for her speech? | ||
| + | |||
| + | |||
| + | <math>\text{(A)}\ 2250 \qquad \text{(B)}\ 3000 \qquad \text{(C)}\ 4200 \qquad \text{(D)}\ 4350 \qquad \text{(E)}\ 5650</math> | ||
| + | |||
| + | |||
| + | |||
| + | ==Solution== | ||
| + | Since there are <math>60</math> minutes in an hour, we need a number of words between <math>(\frac{1}{2}\times 60)\times150=4500</math> and <math>(\frac{3}{4}\times60)\times150=6750</math>. The only such choice is <math>\boxed{\textbf{(E)}}</math>. | ||
| + | |||
| + | == See also == | ||
| + | {{AJHSME box|year=1997|num-b=3|num-a=5}} | ||
| + | * [[AJHSME]] | ||
| + | * [[AJHSME Problems and Solutions]] | ||
| + | * [[Mathematics competition resources]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 23:26, 4 July 2013
Problem
Julie is preparing a speech for her class. Her speech must last between one-half hour and three-quarters of an hour. The ideal rate of speech is 150 words per minute. If Julie speaks at the ideal rate, which of the following number of words would be an appropriate length for her speech?
Solution
Since there are 
minutes in an hour, we need a number of words between 
and 
. The only such choice is 
.
See also
| 1997 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
