Difference between revisions of "1984 AHSME Problems/Problem 3"
m (→Solution) |
Topnotchmath (talk | contribs) |
||
(3 intermediate revisions by 2 users not shown) | |||
Line 10: | Line 10: | ||
{{AHSME box|year=1984|num-b=2|num-a=4}} | {{AHSME box|year=1984|num-b=2|num-a=4}} | ||
+ | {{MAA Notice}} |
Latest revision as of 08:46, 8 November 2016
Problem
Let be the smallest nonprime integer greater than with no prime factor less than . Then
Solution
Since the number isn't prime, it is a product of two primes. If the least integer were a product of more than two primes, then one prime could be removed without making the number prime or introducing any prime factors less than . These prime factors must be greater than , so the least prime factor is . Therefore, the least integer is , which is in .
See Also
1984 AHSME (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.