Difference between revisions of "KGS math club/solution 11 1"
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<li>the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away from the vertex through which that axis passes</li> | <li>the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away from the vertex through which that axis passes</li> | ||
<li>the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away, in the opposite direction, from the vertex through which that axis passes</li> | <li>the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away, in the opposite direction, from the vertex through which that axis passes</li> | ||
| − | <li>Four of the vertices of a pentagon</li> | + | <li>Four of the vertices of a regular pentagon</li> |
</ol> | </ol> | ||
Latest revision as of 10:08, 11 May 2011
There are six ways:
- the vertices of a square
- the vertices of a 60-degree rhombus
- the vertices of an equlateral triangle, plus its midpoint
- the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away from the vertex through which that axis passes
- the vertices of an equlateral triangle, plus a point on a symmetry axis that is a side-length away, in the opposite direction, from the vertex through which that axis passes
- Four of the vertices of a regular pentagon
