Difference between revisions of "2010 AMC 10B Problems/Problem 2"

Latest revision as of 19:35, 26 May 2020

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-Makarla attended two meetings during her <math>9</math>-hour work day. The first meeting took <math>45</math> minutes and the second meeting took twice as long. What percent of her work day was spent attending meetings?
+#redirect [[2010 AMC 12B Problems/Problem 1]]
-<cmath> \textbf{(A)}\ 15\qquad\textbf{(B)}\ 20\qquad\textbf{(C)}\ 25\qquad\textbf{(D)}\ 30\qquad\textbf{(E)}\ 35 </cmath>
-The percentage of her time spent in meetings is the total amount of time spent in meetings divided by the length of her workday.
-The total time spent in meetings is <math>45 \text{ min}  + 2*45\text{ min} = 2\text{ hours } 15 \text{ min} = 9/4 \text{ hours}</math>
-Therefore, the percentage is <cmath>\frac{9/4 \text{ hours} }{9 \text{ hours}} = \frac{1}{4} = 25 \% = \textbf{(C)}</cmath>