Difference between revisions of "1987 AJHSME Problems/Problem 5"
5849206328x (talk | contribs) (New page: ==Problem== The area of the rectangular region is <asy> draw((0,0)--(4,0)--(4,2.2)--(0,2.2)--cycle,linewidth(.5 mm)); label(".22 m",(4,1.1),E); label(".4 m",(2,0),S); </asy> <math>\tex...) |
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==Solution== | ==Solution== | ||
| − | {{ | + | <math>(.4) \cdot (.22) = \frac{4}{10} \cdot \frac{22}{100} = \frac{4\cdot 22}{10\cdot 100} = \frac{88}{1000} = 0.088\rightarrow \boxed{\text{A}}</math> |
==See Also== | ==See Also== | ||
| − | [[ | + | {{AJHSME box|year=1987|num-b=4|num-a=6}} |
| + | [[Category:Introductory Geometry Problems]] | ||
| + | {{MAA Notice}} | ||
Latest revision as of 22:52, 4 July 2013
Problem
The area of the rectangular region is
![[asy] draw((0,0)--(4,0)--(4,2.2)--(0,2.2)--cycle,linewidth(.5 mm)); label(".22 m",(4,1.1),E); label(".4 m",(2,0),S); [/asy]](http://latex.artofproblemsolving.com/8/c/c/8cc290473bf98b3c78b84fe4028b8f76279b0e54.png)
Solution
See Also
| 1987 AJHSME (Problems • Answer Key • Resources) | ||
| Preceded by Problem 4 |
Followed by Problem 6 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
