Difference between revisions of "2000 AMC 10 Problems/Problem 9"

Latest revision as of 22:37, 26 November 2011

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-==Problem==
+#REDIRECT [[2000 AMC 12 Problems/Problem 5]]
-==Solution==
-<math>|x-2|=p</math>
-<math>x<2</math>, so <math>2-x=p</math>.
-<math>x+p=2</math>.
-<math>x-p=2-2p</math>.
-<math>\boxed{\text{C}}</math>
-==See Also==
-{{AMC10 box|year=2000|num-b=8|num-a=10}}