Difference between revisions of "2006 AMC 10B Problems/Problem 3"

(Solution 2)
m (Solution 2: fix)
 
(4 intermediate revisions by the same user not shown)
Line 6: Line 6:
 
== Solution ==
 
== Solution ==
 
Let <math>x</math> be the number of points scored by the Cougars, and <math>y</math> be the number of points scored by the Panthers. The problem is asking for the value of <math>y</math>.  
 
Let <math>x</math> be the number of points scored by the Cougars, and <math>y</math> be the number of points scored by the Panthers. The problem is asking for the value of <math>y</math>.  
<math></math>\begin{align*}
+
<cmath>\begin{align*}
 
x+y &= 34 \\
 
x+y &= 34 \\
 
x-y &= 14 \\
 
x-y &= 14 \\
 
2x &= 48 \\
 
2x &= 48 \\
 
x &= 24 \\
 
x &= 24 \\
The answer is <math>(A) 10</math>
+
\end{align*}</cmath>
 +
The answer is <math>\boxed{\textbf{(A) } 10}</math>
  
 
== Solution 2 ==
 
== Solution 2 ==
Line 19: Line 20:
 
<math>p = 10</math>.
 
<math>p = 10</math>.
  
 
+
<cmath>\begin{align*}
 +
p &= \boxed{\textbf{(A) }10} \\
 +
\end{align*}</cmath>
  
 
-- leafy
 
-- leafy

Latest revision as of 09:31, 24 February 2025

Problem

A football game was played between two teams, the Cougars and the Panthers. The two teams scored a total of $34$ points, and the Cougars won by a margin of $14$ points. How many points did the Panthers score?

$\textbf{(A) } 10\qquad \textbf{(B) } 14\qquad \textbf{(C) } 17\qquad \textbf{(D) } 20\qquad \textbf{(E) } 24$

Solution

Let $x$ be the number of points scored by the Cougars, and $y$ be the number of points scored by the Panthers. The problem is asking for the value of $y$. \begin{align*} x+y &= 34 \\ x-y &= 14 \\ 2x &= 48 \\ x &= 24 \\ \end{align*} The answer is $\boxed{\textbf{(A) } 10}$

Solution 2

$c$ is the amount the Cougars scored and $p$ is the score for Panthers. Since the Cougars won by 14 points, $c = p + 14$. Using substitution, $2p + 14 = 34$, $2p = 20$, and then $p = 10$.

\begin{align*} p &= \boxed{\textbf{(A) }10} \\ \end{align*}

-- leafy

See Also

2006 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png