Difference between revisions of "2022 AMC 8 Problems/Problem 17"
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− | ==Problem== | + | == Problem == |
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If <math>n</math> is an even positive integer, the <math>\emph{double factorial}</math> notation <math>n!!</math> represents the product of all the even integers from <math>2</math> to <math>n</math>. For example, <math>8!! = 2 \cdot 4 \cdot 6 \cdot 8</math>. What is the units digit of the following sum? <cmath>2!! + 4!! + 6!! + \cdots + 2018!! + 2020!! + 2022!!</cmath> | If <math>n</math> is an even positive integer, the <math>\emph{double factorial}</math> notation <math>n!!</math> represents the product of all the even integers from <math>2</math> to <math>n</math>. For example, <math>8!! = 2 \cdot 4 \cdot 6 \cdot 8</math>. What is the units digit of the following sum? <cmath>2!! + 4!! + 6!! + \cdots + 2018!! + 2020!! + 2022!!</cmath> | ||
<math>\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8</math> | <math>\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8</math> | ||
− | ==Solution== | + | == Solution 1 == |
Notice that once <math>n>8,</math> the units digit of <math>n!!</math> will be <math>0</math> because there will be a factor of <math>10.</math> Thus, we only need to calculate the units digit of <cmath>2!!+4!!+6!!+8!! = 2+8+48+48\cdot8.</cmath> We only care about units digits, so we have <math>2+8+8+8\cdot8,</math> which has the same units digit as <math>2+8+8+4.</math> The answer is <math>\boxed{\textbf{(B) } 2}.</math> | Notice that once <math>n>8,</math> the units digit of <math>n!!</math> will be <math>0</math> because there will be a factor of <math>10.</math> Thus, we only need to calculate the units digit of <cmath>2!!+4!!+6!!+8!! = 2+8+48+48\cdot8.</cmath> We only care about units digits, so we have <math>2+8+8+8\cdot8,</math> which has the same units digit as <math>2+8+8+4.</math> The answer is <math>\boxed{\textbf{(B) } 2}.</math> | ||
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~wamofan | ~wamofan | ||
− | ==Video Solution | + | == Video Solution 1 == |
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− | + | [//youtu.be/tYWp6fcUAik?si=V8hv_zOn_zYOi9E5&t=2049 ~hsnacademy] | |
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− | + | == Video Solution 2 == | |
− | ==Video Solution | + | [//youtu.be/oUEa7AjMF2A?si=f4lLO32DQ4Yxdpkv&t=2925 ~Math-X] |
− | + | ||
+ | ==Video Solution 3 == | ||
− | ~Education, the Study of Everything | + | [//youtu.be/qOBzhBx8uw4 ~Education, the Study of Everything] |
+ | |||
+ | == Video Solution 4 == | ||
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https://youtu.be/wp9tOyJ3YQY?t=146 | https://youtu.be/wp9tOyJ3YQY?t=146 | ||
− | ==Video Solution== | + | == Video Solution 5 == |
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− | ~Interstigation | + | [//youtu.be/Ij9pAy6tQSg?t=1461 ~Interstigation] |
− | + | == Video Solution 6 == | |
− | ~ | + | [//youtu.be/hs6y4PWnoWg?t=80 ~STEMbreezy] |
− | ==Video Solution== | + | == Video Solution 7 == |
− | + | [//youtu.be/BbGqQaqE2rM ~savannahsolver] | |
− | + | == Video Solution 8 == | |
− | + | [//www.youtube.com/watch?v=EVYrVkkpCo8 ~Jamesmath] | |
− | |||
− | + | == Video Solution 9 == | |
− | + | https://youtu.be/1Vg8Mt0bSbQ | |
− | https:// | ||
− | + | == Video Solution 10 == | |
− | == | + | [//youtube.com/FTVLuv_n9bY ~Ismail.Maths] |
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+ | == See Also == | ||
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{{AMC8 box|year=2022|num-b=16|num-a=18}} | {{AMC8 box|year=2022|num-b=16|num-a=18}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
+ | [[Category:Introductory Number Theory Problems]] |
Latest revision as of 09:17, 22 February 2025
Contents
Problem
If is an even positive integer, the
notation
represents the product of all the even integers from
to
. For example,
. What is the units digit of the following sum?
Solution 1
Notice that once the units digit of
will be
because there will be a factor of
Thus, we only need to calculate the units digit of
We only care about units digits, so we have
which has the same units digit as
The answer is
~wamofan
Video Solution 1
Video Solution 2
Video Solution 3
~Education, the Study of Everything
Video Solution 4
https://youtu.be/wp9tOyJ3YQY?t=146
Video Solution 5
Video Solution 6
Video Solution 7
Video Solution 8
Video Solution 9
Video Solution 10
See Also
2022 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 16 |
Followed by Problem 18 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.