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Difference between revisions of "2024 AMC 12B Problems/Problem 14"
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We split the cases into:
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#REDIRECT[[2024 AMC 10B Problems/Problem 18]]
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1. If x is not a multiple of 5:
 
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we get x^100 \equiv 1 (mod 125)
 
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2. If x is a multiple of 125:
 
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Clearly the only remainder provides 0
 
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Therefore, the remainders can only be 1 and 0, which gives the answer (B)2
 
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~mitsuihisashi14
 

Latest revision as of 01:24, 14 November 2024

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