Difference between revisions of "1951 AHSME Problems/Problem 4"
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The walls are <math>13*5=65</math> and <math>10*5=50</math> in area, and the ceiling has an area of <math>10*13=130</math>. | The walls are <math>13*5=65</math> and <math>10*5=50</math> in area, and the ceiling has an area of <math>10*13=130</math>. | ||
− | <math>((65+50)2)2+130=590 \Rightarrow \boxed{\mathrm{(D) | + | <math>((65+50)2)2+130=590 \Rightarrow \boxed{\mathrm{(D)}}</math> |
− | ==See | + | ==See Also== |
+ | {{AHSME 50p box|year=1951|num-b=3|num-a=5}} | ||
+ | |||
+ | [[Category:Introductory Geometry Problems]] | ||
+ | {{MAA Notice}} |
Latest revision as of 11:19, 5 July 2013
Problem
A barn with a roof is rectangular in shape, yd. wide, yd. long and yd. high. It is to be painted inside and outside, and on the ceiling, but not on the roof or floor. The total number of sq. yd. to be painted is:
Solution
The walls are and in area, and the ceiling has an area of .
See Also
1951 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 3 |
Followed by Problem 5 | |
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All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.