Difference between revisions of "1957 AHSME Problems/Problem 23"
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We can merge the two equations to create <math>x^2+y=x+y</math>. Using either the quadratic equation or factoring, we get two solutions with <math>x</math>-coordinates <math>0</math> and <math>1</math>. | We can merge the two equations to create <math>x^2+y=x+y</math>. Using either the quadratic equation or factoring, we get two solutions with <math>x</math>-coordinates <math>0</math> and <math>1</math>. | ||
− | Plugging this into either of the original equations, we get <math>(0,10)</math> and <math>(1,9)</math>. The distance between those two points is <math>\boxed{\textbf{(C) }\sqrt{2}}</math> | + | Plugging this into either of the original equations, we get <math>(0,10)</math> and <math>(1,9)</math>. The [[distance formula|distance]] between those two points is <math>\boxed{\textbf{(C) }\sqrt{2}}</math>. |
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==See Also== | ==See Also== | ||
{{AHSME 50p box|year=1957|num-b=22|num-a=24}} | {{AHSME 50p box|year=1957|num-b=22|num-a=24}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
[[Category:AHSME]][[Category:AHSME Problems]] | [[Category:AHSME]][[Category:AHSME Problems]] |
Latest revision as of 09:10, 25 July 2024
The graph of and the graph of meet in two points. The distance between these two points is:
Solution
We can merge the two equations to create . Using either the quadratic equation or factoring, we get two solutions with -coordinates and .
Plugging this into either of the original equations, we get and . The distance between those two points is .
See Also
1957 AHSC (Problems • Answer Key • Resources) | ||
Preceded by Problem 22 |
Followed by Problem 24 | |
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All AHSME Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.