Art of Problem Solving
AoPS Online
Math texts, online classes, and more
for students in grades 5-12.
Visit AoPS Online ‚
Books for Grades 5-12 Online Courses
Beast Academy
Engaging math books and online learning
for students ages 6-13.
Visit Beast Academy ‚
Books for Ages 6-13 Beast Academy Online
AoPS Academy
Small live classes for advanced math
and language arts learners in grades 2-12.
Visit AoPS Academy ‚
Find a Physical Campus Visit the Virtual Campus

Difference between revisions of "2006 AMC 10A Problems/Problem 18"
(→‎Video Solution by OmegaLearn)
 
(One intermediate revision by one other user not shown)
Line 14: Line 14:
 
Therefore, the number of distinct license plates is  <math> 5\times 10^4\times 26^2 \Longrightarrow \boxed{\mathrm{C}}</math>.
 
Therefore, the number of distinct license plates is  <math> 5\times 10^4\times 26^2 \Longrightarrow \boxed{\mathrm{C}}</math>.
  
−
== Solution 2 ==
+
== Solution 2 (Answer choices) ==
 
There are <math>10^4</math> ways to choose the digits and <math>26^2</math> ways to choose the 2 letters. However, since the letters are next to each other, the result must be <math>10^4\cdot 26^2 \cdot \text{something}</math>. The only answer choice that matches this is <math>\boxed{\mathrm{C}}</math>.
 
There are <math>10^4</math> ways to choose the digits and <math>26^2</math> ways to choose the 2 letters. However, since the letters are next to each other, the result must be <math>10^4\cdot 26^2 \cdot \text{something}</math>. The only answer choice that matches this is <math>\boxed{\mathrm{C}}</math>.
  
Line 21: Line 21:
 
==Video Solution by OmegaLearn==
 
==Video Solution by OmegaLearn==
 
https://youtu.be/0W3VmFp55cM?t=847
 
https://youtu.be/0W3VmFp55cM?t=847
−
 
−
~ pi_is_3.14
 
  
 
== Video Solutions ==
 
== Video Solutions ==

Latest revision as of 14:33, 30 July 2024

Problem

A license plate in a certain state consists of $4$ digits, not necessarily distinct, and $2$ letters, also not necessarily distinct. These six characters may appear in any order, except that the two letters must appear next to each other. How many distinct license plates are possible?

$\textbf{(A) } 10^4\times 26^2\qquad\textbf{(B) } 10^3\times 26^3\qquad\textbf{(C) } 5\times 10^4\times 26^2\qquad\textbf{(D) } 10^2\times 26^4\qquad\textbf{(E) } 5\times 10^3\times 26^3\qquad$

Solution

There are $10\cdot10\cdot10\cdot10 = 10^4$ ways to choose 4 digits.

There are $26 \cdot 26 = 26^2$ ways to choose the 2 letters.

For the letters to be next to each other, they can be the 1st and 2nd, 2nd and 3rd, 3rd and 4th, 4th and 5th, or the 5th and 6th characters. So, there are $6 - 1 = 5$ choices for the position of the letters.

Therefore, the number of distinct license plates is $5\times 10^4\times 26^2 \Longrightarrow \boxed{\mathrm{C}}$.

Solution 2 (Answer choices)

There are $10^4$ ways to choose the digits and $26^2$ ways to choose the 2 letters. However, since the letters are next to each other, the result must be $10^4\cdot 26^2 \cdot \text{something}$. The only answer choice that matches this is $\boxed{\mathrm{C}}$.

~ Andrew2019

Video Solution by OmegaLearn

https://youtu.be/0W3VmFp55cM?t=847

Video Solutions

https://youtu.be/3MiGotKnC_U?t=1446

~ThePuzzlr


https://youtu.be/f56aG55oG8w

~savannahsolver

See also

2006 AMC 10A (Problems • Answer Key • Resources)
Preceded by
Problem 17 		Followed by
Problem 19
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
All AMC 10 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=2006_AMC_10A_Problems/Problem_18&oldid=223997"