Difference between revisions of "2013 CEMC Gauss (Grade 7) Problems/Problem 6"

Latest revision as of 17:36, 21 August 2024

Nick has six nickels (5¢ coins), two dimes (10¢ coins) and one quarter (25¢ coin). In cents (¢), how much money does Nick have?

$\textbf{(A)}\ 65\qquad\textbf{(B)}\ 75\qquad\textbf{(C)}\ 35\qquad\textbf{(D)}\ 15\qquad\textbf{(E)}\ 55$

We can change the problem to 6x5+2x10+1x25 = 30+20+25 which is equal to $\boxed{ \textbf{(B) }75 }$

Revision as of 16:57, 20 January 2024 (view source) Mathalausthegreekgod (talk \| contribs) (Created page with "==Problem 6== Nick has six nickels (5¢ coins), two dimes (10¢ coins) and one quarter (25¢ coin). In cents (¢), how much money does Nick have? <math> \textbf{(A)}\ 65\qqua...")		Latest revision as of 17:36, 21 August 2024 (view source) Mathalausthegreekgod (talk \| contribs) (→‎Solution)
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	==Solution==		==Solution==
−	We can change the problem to (6x5)+(2x10)+(1x25~~) which can be evaluated as (~~30)+(20)+(25) which is equal to <math>\boxed{ \textbf{(B) }75 }</math>	+	We can change the problem to 6x5+2x10+1x25 = 30+20+25 which is equal to <math>\boxed{ \textbf{(B) }75 }</math>