Art of Problem Solving
AoPS Online
Math texts, online classes, and more
for students in grades 5-12.
Visit AoPS Online ‚
Books for Grades 5-12 Online Courses
Beast Academy
Engaging math books and online learning
for students ages 6-13.
Visit Beast Academy ‚
Books for Ages 6-13 Beast Academy Online
AoPS Academy
Small live classes for advanced math
and language arts learners in grades 2-12.
Visit AoPS Academy ‚
Find a Physical Campus Visit the Virtual Campus

Difference between revisions of "1984 USAMO Problems/Problem 3"

(→‎Solution)
(→‎Solution)
 
(2 intermediate revisions by the same user not shown)
Line 6: Line 6:
 
Greatest value is achieved when all the points are as close as possible to all being on a plane.
 
Greatest value is achieved when all the points are as close as possible to all being on a plane.
  
−
Since <math>\theta \le \frac{\pi}{2}</math>, then <math>\angle APC + \angle BPD le \pi</math>
+
Since <math>\theta < \frac{\pi}{2}</math>, then <math>\angle APC + \angle BPD < \pi</math>
  
−
Smallest value is achieved when point P is above and the remaining points are as close as possible to colinear when <math>\theta \ge 0</math>, then <math>\angle APC + \angle BPD \ge 0</math>
+
Smallest value is achieved when point P is above and the remaining points are as close as possible to colinear when <math>\theta > 0</math>, then <math>\angle APC + \angle BPD > 0</math>
  
 
and the inequality for this problem is:
 
and the inequality for this problem is:
  
−
<math>0 \le \angle APC + \angle BPD le \pi</math>
+
<math>0 < \angle APC + \angle BPD < \pi</math>
  
 
~Tomas Diaz. orders@tomasdiaz.com
 
~Tomas Diaz. orders@tomasdiaz.com

Latest revision as of 01:26, 21 November 2023

Problem

$P$, $A$, $B$, $C$, and $D$ are five distinct points in space such that $\angle APB = \angle BPC = \angle CPD = \angle DPA = \theta$, where $\theta$ is a given acute angle. Determine the greatest and least values of $\angle APC + \angle BPD$.

Solution

Greatest value is achieved when all the points are as close as possible to all being on a plane.

Since $\theta < \frac{\pi}{2}$, then $\angle APC + \angle BPD < \pi$

Smallest value is achieved when point P is above and the remaining points are as close as possible to colinear when $\theta > 0$, then $\angle APC + \angle BPD > 0$

and the inequality for this problem is:

$0 < \angle APC + \angle BPD < \pi$

~Tomas Diaz. orders@tomasdiaz.com

Alternate solutions are always welcome. If you have a different, elegant solution to this problem, please add it to this page.

See Also

1984 USAMO (Problems • Resources)
Preceded by
Problem 2 		Followed by
Problem 4
1 • 2 • 3 • 4 • 5
All USAMO Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Retrieved from "https://artofproblemsolving.com/wiki/index.php?title=1984_USAMO_Problems/Problem_3&oldid=205051"