Difference between revisions of "2019 AMC 8 Problems/Problem 8"

(Video Solution (CREATIVE THINKING!!!))
 
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==Problem 8==
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==Problem==
 
Gilda has a bag of marbles. She gives <math>20\%</math> of them to her friend Pedro. Then Gilda gives <math>10\%</math> of what is left to another friend, Ebony. Finally, Gilda gives <math>25\%</math> of what is now left in the bag to her brother Jimmy. What percentage of her original bag of marbles does Gilda have left for herself?
 
Gilda has a bag of marbles. She gives <math>20\%</math> of them to her friend Pedro. Then Gilda gives <math>10\%</math> of what is left to another friend, Ebony. Finally, Gilda gives <math>25\%</math> of what is now left in the bag to her brother Jimmy. What percentage of her original bag of marbles does Gilda have left for herself?
  
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== Video Solution ==
 
== Video Solution ==
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==Video Solution by Math-X (Do percentage questions like this!!!)==
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https://youtu.be/IgpayYB48C4?si=_eGyqshtrNAg3tAm&t=2362
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~Math-X
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The Learning Royal : https://youtu.be/8njQzoztDGc
 
The Learning Royal : https://youtu.be/8njQzoztDGc
 
== Video Solution 2 ==
 
== Video Solution 2 ==
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~Education, the Study of Everything
 
~Education, the Study of Everything
  
==Video Solution by The Power of Logic(Problem 1 to 25 Full Solution)==
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==Video Solution by The Power of Logic(1 to 25 Full Solution)==
 
https://youtu.be/Xm4ZGND9WoY
 
https://youtu.be/Xm4ZGND9WoY
  

Latest revision as of 09:30, 9 November 2024

Problem

Gilda has a bag of marbles. She gives $20\%$ of them to her friend Pedro. Then Gilda gives $10\%$ of what is left to another friend, Ebony. Finally, Gilda gives $25\%$ of what is now left in the bag to her brother Jimmy. What percentage of her original bag of marbles does Gilda have left for herself?

$\textbf{(A) }20\qquad\textbf{(B) }33\frac{1}{3}\qquad\textbf{(C) }38\qquad\textbf{(D) }45\qquad\textbf{(E) }54$

Solution 1

After Gilda gives $20$% of the marbles to Pedro, she has $80$% of the marbles left. If she then gives $10$% of what's left to Ebony, she has $(0.8*0.9)$ = $72$% of what she had at the beginning. Finally, she gives $25$% of what's left to her brother, so she has $(0.75*0.72)$ $\boxed{\textbf{(E)}\ 54}$ of what she had in the beginning left.

Solution 2

Suppose Gilda has 100 marbles.

Then, she gives Pedro 20% of 100 = 20, she remains with 80 marbles.

Out of 80 marbles, she gives 10% of 80 = 8 to Ebony.

Thus, she remains with 72 marbles.

Then, she gives 25% of 72 = 18 to Jimmy, finally leaving her with 54.

And, $\frac{54}{100}$=54%=$\boxed{\textbf{(E)}\ 54}$.

~phoenixfire

Solution 3

(Only if you have lots of time do it this way) Since she gave away 20% and 10% of what is left and then another 25% of what is actually left, we can do 20+10+25 or 55%. But it is actually going to be a bit more than 55% because 10% of what is left is not 10% of the total amount. So, the only option that is greater than 100% - 55% is $\boxed{\textbf{(E)}\ 54}$.

Video Solution

Video Solution by Math-X (Do percentage questions like this!!!)

https://youtu.be/IgpayYB48C4?si=_eGyqshtrNAg3tAm&t=2362

~Math-X

The Learning Royal : https://youtu.be/8njQzoztDGc

Video Solution 2

Solution detailing how to solve the problem: https://www.youtube.com/watch?v=WAmvVQzuzfc&list=PLbhMrFqoXXwmwbk2CWeYOYPRbGtmdPUhL&index=9

Video Solution 3

https://youtu.be/Cwnq8XRxJ6Y Soo, DRMS, NM

Video Solution 4

https://youtu.be/eApJGrvDT5U

~savannahsolver

Video Solution (CREATIVE THINKING!!!)

https://youtu.be/yAdewhYZ3Uc

~Education, the Study of Everything

Video Solution by The Power of Logic(1 to 25 Full Solution)

https://youtu.be/Xm4ZGND9WoY

~Hayabusa1

See also

2019 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 9
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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