Difference between revisions of "User talk:Kaisssssgao"

(Solution 2)
(Solution 2)
 
(4 intermediate revisions by the same user not shown)
Line 20: Line 20:
 
=Solution 2=
 
=Solution 2=
  
according to L'Hopital rule, that lim x->c f(x)/g(x)=li x-> f'(x)/g'(x), rewrite 1+1=1+1/1, according to the theorem, set 1=f(X) f'(x)=0, set 1=g(x),so g'(x)=0, so 1+1=undefined we chose (E)~Kai Gao
+
according to L'Hopital rule, that lim x->c f(x)/g(x)=lim x->c f'(x)/g'(x), rewrite 1+1=1+1/1, according to the theorem, set 1=f(X) f'(x)=0, set 1=g(x),so g'(x)=0, so 1+1=undefined we chose (E)~Kai Gao
  
 
=Solution 3=
 
=Solution 3=
 
never gonna give u up.
 
never gonna give u up.
 
=Video solution=
 
https://youtu.be/QDjPvLYuRDA
 
 
=Video solution2=
 
https://www.thinkacademy.ca/courses/detail/35283
 
 
=Video solution3=
 
https://youtu.be/dQw4w9WgXcQ
 

Latest revision as of 01:16, 7 July 2023

QUESTION

WHAT'S THE VALUE OF 1+1?


A)3

B)4

C)5

D)6

E)undefined

Solution greg346 1

according to kai's theorem, so we chose (A) 1+1=3~Tyler Xiang

Solution 2

according to L'Hopital rule, that lim x->c f(x)/g(x)=lim x->c f'(x)/g'(x), rewrite 1+1=1+1/1, according to the theorem, set 1=f(X) f'(x)=0, set 1=g(x),so g'(x)=0, so 1+1=undefined we chose (E)~Kai Gao

Solution 3

never gonna give u up.