Difference between revisions of "2002 AMC 8 Problems/Problem 9"

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==Juan's Old Stamping Grounds==
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==Problem==
  
 
Problems 8,9 and 10 use the data found in the accompanying paragraph and table:
 
Problems 8,9 and 10 use the data found in the accompanying paragraph and table:
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label(scale(0.9)*"Number of Stamps by Decade", (9,5), N);</asy>
 
label(scale(0.9)*"Number of Stamps by Decade", (9,5), N);</asy>
  
==Problem==
 
 
In dollars and cents, how much did his South American stamps issued before the ’70s cost him?
 
In dollars and cents, how much did his South American stamps issued before the ’70s cost him?
  
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==Solution==
 
==Solution==
 
Brazil 50s and 60s total 11 stamps with each 6 cents, Peru 50s and 60s total 10 stamps with each 4 cents. So total <math>11*0.06+10*0.04 = \boxed{\text{(B)}\ \$1.06}</math>  
 
Brazil 50s and 60s total 11 stamps with each 6 cents, Peru 50s and 60s total 10 stamps with each 4 cents. So total <math>11*0.06+10*0.04 = \boxed{\text{(B)}\ \$1.06}</math>  
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==Video Solution by WhyMath==
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https://youtu.be/RWqatORHMow
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2002|num-b=8|num-a=10}}
 
{{AMC8 box|year=2002|num-b=8|num-a=10}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 13:29, 29 October 2024

Problem

Problems 8,9 and 10 use the data found in the accompanying paragraph and table:

Juan organizes the stamps in his collection by country and by the decade in which they were issued. The prices he paid for them at a stamp shop were: Brazil and France, 6 cents each, Peru 4 cents each, and Spain 5 cents each. (Brazil and Peru are South American countries and France and Spain are in Europe.)

[asy] /* AMC8 2002 #8, 9, 10 Problem */ size(3inch, 1.5inch); for ( int y = 0; y &lt;= 5; ++y ) { draw((0,y)--(18,y)); } draw((0,0)--(0,5)); draw((6,0)--(6,5)); draw((9,0)--(9,5)); draw((12,0)--(12,5)); draw((15,0)--(15,5)); draw((18,0)--(18,5)); draw(scale(0.8)*"50s", (7.5,4.5)); draw(scale(0.8)*"4", (7.5,3.5)); draw(scale(0.8)*"8", (7.5,2.5)); draw(scale(0.8)*"6", (7.5,1.5)); draw(scale(0.8)*"3", (7.5,0.5)); draw(scale(0.8)*"60s", (10.5,4.5)); draw(scale(0.8)*"7", (10.5,3.5)); draw(scale(0.8)*"4", (10.5,2.5)); draw(scale(0.8)*"4", (10.5,1.5)); draw(scale(0.8)*"9", (10.5,0.5)); draw(scale(0.8)*"70s", (13.5,4.5)); draw(scale(0.8)*"12", (13.5,3.5)); draw(scale(0.8)*"12", (13.5,2.5)); draw(scale(0.8)*"6", (13.5,1.5)); draw(scale(0.8)*"13", (13.5,0.5)); draw(scale(0.8)*"80s", (16.5,4.5)); draw(scale(0.8)*"8", (16.5,3.5)); draw(scale(0.8)*"15", (16.5,2.5)); draw(scale(0.8)*"10", (16.5,1.5)); draw(scale(0.8)*"9", (16.5,0.5)); label(scale(0.8)*"Country", (3,4.5)); label(scale(0.8)*"Brazil", (3,3.5)); label(scale(0.8)*"France", (3,2.5)); label(scale(0.8)*"Peru", (3,1.5)); label(scale(0.8)*"Spain", (3,0.5)); label(scale(0.9)*"Juan's Stamp Collection", (9,0), S); label(scale(0.9)*"Number of Stamps by Decade", (9,5), N);[/asy]

In dollars and cents, how much did his South American stamps issued before the ’70s cost him?

$\text{(A)}\ $0.40 \qquad \text{(B)}\ $1.06 \qquad \text{(C)}\ $1.80 \qquad \text{(D)}\ $2.38 \qquad \text{(E)}\ $2.64$

Solution

Brazil 50s and 60s total 11 stamps with each 6 cents, Peru 50s and 60s total 10 stamps with each 4 cents. So total $11*0.06+10*0.04 = \boxed{\text{(B)}\ $1.06}$

Video Solution by WhyMath

https://youtu.be/RWqatORHMow

See Also

2002 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 8
Followed by
Problem 10
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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