Difference between revisions of "2010 AMC 8 Problems/Problem 4"

 
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~ pi_is_3.14
 
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==Video by MathTalks==
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https://youtu.be/EEbksvfujhk
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==Video Solution by WhyMath==
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https://youtu.be/Bxscjb2WaSw
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2010|num-b=3|num-a=5}}
 
{{AMC8 box|year=2010|num-b=3|num-a=5}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 10:24, 18 November 2024

Problem

What is the sum of the mean, median, and mode of the numbers $2,3,0,3,1,4,0,3$?

$\textbf{(A)}\ 6.5 \qquad\textbf{(B)}\ 7\qquad\textbf{(C)}\ 7.5\qquad\textbf{(D)}\ 8.5\qquad\textbf{(E)}\ 9$

Solution

Putting the numbers in numerical order we get the list $0,0,1,2,3,3,3,4.$ The mode is $3.$ The median is $\frac{2+3}{2}=2.5.$ The average is $\frac{0+0+1+2+3+3+3+4}{8}=\frac{16}{8}=2.$ The sum of all three is $3+2.5+2=\boxed{\textbf{(C)}\ 7.5}$

Video Solution by OmegaLearn

https://youtu.be/51K3uCzntWs?t=209

~ pi_is_3.14


Video by MathTalks

https://youtu.be/EEbksvfujhk

Video Solution by WhyMath

https://youtu.be/Bxscjb2WaSw

See Also

2010 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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