Difference between revisions of "2006 Seniors Pancyprian/2nd grade/Problems"
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== Problem 5 == | == Problem 5 == | ||
− | Fifty persons, twenty five boys and twenty five girls are sitting around a table. Prove that there is a person | + | Fifty persons, twenty five boys and twenty five girls are sitting around a table. Prove that there is a person out of 50 who is sitting between two girls. |
[[2006 Seniors Pancyprian/2nd grade/Problem 5|Solution]] | [[2006 Seniors Pancyprian/2nd grade/Problem 5|Solution]] |
Latest revision as of 11:19, 10 October 2007
Problem 1
Let be a given triangle and the midpoint of the side . The circle with diameter cuts at and form we bring ( is out of the triangle). Prove that the area of the quadrilateral is equal to the area of the triangle .
Problem 2
Find all three digit numbers (=100x+10y+z) for which .
Problem 3
i)Convert $\Alpha=sin(x-y)+sin(y-z)+sin(z-x)$ (Error compiling LaTeX. Unknown error_msg) into product.
ii)Prove that: If in a triangle $\Alpha\Beta\Gamma$ (Error compiling LaTeX. Unknown error_msg) is true that $\alpha sin \Beta + \beta sin \Gamma + \gamma sin \Alpha= \frac {\alpha+\beta+\gamma}{2}$ (Error compiling LaTeX. Unknown error_msg), then the triangle is isosceles.
Problem 4
A quadrilateral , that has no parallel sides, is inscribed in a circle, its sides , meet at and its sides , meet at . If the bisectors of and intersect the sides of the quadrilateral at th points prove that
i)the bisectors intersect normally
ii)the points are vertices of a rhombus.
Problem 5
Fifty persons, twenty five boys and twenty five girls are sitting around a table. Prove that there is a person out of 50 who is sitting between two girls.