Difference between revisions of "1997 PMWC Problems/Problem I10"
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==Problem== | ==Problem== | ||
| − | Mary took 24 chickens to the market. In the morning she | + | Mary took <math>24</math> chickens to the market. In the morning she sold the chickens at <math>\textdollar 7</math> each and she only sold out less than half of them. In the afternoon she discounted the price of each chicken but the price was still an integral number in dollar. In the afternoon she could sell all the chickens, and she got totally <math>\textdollar 132</math> for the whole day. How many chickens were sold in the morning? |
| − | sold the chickens at <math>\</math> | ||
| − | half of them. In the afternoon she discounted the price of | ||
| − | each chicken but the price was still an integral number in | ||
| − | dollar. In the afternoon she could sell all the chickens, and | ||
| − | she got totally <math>\</math> | ||
| − | chickens were sold in the morning? | ||
==Solution== | ==Solution== | ||
| − | Let A be the number of chickens she sold before the discount and B be the number of chickens sold after the discount. Let c be the price of one chicken after the discount. | + | Let <math>A</math> be the number of chickens she sold before the discount and <math>B</math> be the number of chickens sold after the discount. Let <math>c</math> be the price of one chicken after the discount. |
<math>A+B=24</math> | <math>A+B=24</math> | ||
| Line 18: | Line 12: | ||
<math>(7-c)(A)=132-24c</math> | <math>(7-c)(A)=132-24c</math> | ||
| − | So c is 5 | + | So <math>c</math> is less than <math>5</math>. We make a table of <math>A</math> and <math>c</math>: |
| − | c|A | + | <math>c</math> | <math>A</math> |
| − | |||
| − | |||
| − | + | <math>5</math> | <math>6</math> | |
| − | A=6. | + | <math>4</math> | <math>18</math> |
| + | |||
| + | So <math>c</math> must equal <math>5</math>, since when <math>c</math> decreases, <math>A</math> increases. | ||
| + | |||
| + | <math>A=6</math>. | ||
| + | |||
| + | == See Also == | ||
| + | {{PMWC box|year=1997|num-b=I9|num-a=I11}} | ||
| + | |||
| + | [[Category:Introductory Algebra Problems]] | ||
Latest revision as of 18:14, 7 April 2016
Problem
Mary took 
chickens to the market. In the morning she sold the chickens at 
each and she only sold out less than half of them. In the afternoon she discounted the price of each chicken but the price was still an integral number in dollar. In the afternoon she could sell all the chickens, and she got totally 
for the whole day. How many chickens were sold in the morning?
Solution
Let 
be the number of chickens she sold before the discount and 
be the number of chickens sold after the discount. Let 
be the price of one chicken after the discount.
So is less than 
. We make a table of and :
|
| 
| 
So must equal , since when decreases, increases.
.
See Also
| 1997 PMWC (Problems) | ||
| Preceded by Problem I9 |
Followed by Problem I11 | |
| I: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 T: 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 | ||
